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Author Topic: Angle of reentry.  (Read 3049 times)

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Offline apokliptico

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01 March 2009, 06:17:00
Hi!
I just wanted to ask for the formula that is used to calculate the angle of reentry in DGIV.

Thanks!
APOKLIPTICO


Offline apokliptico

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Reply #1 - 09 March 2009, 03:00:53
Please!! does anyone know??
Dan?


Offline apokliptico

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Reply #2 - 10 March 2009, 16:14:34
Cmon!, no answers at all???


Offline markl316

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Reply #3 - 06 April 2009, 05:57:45
Depending on how far you do your deorbit burn, it could be anywhere from 35-45.  If you do your deorbit burn from
about 18.00M from the base from a 300k x 300k orbit, 40 degrees should do it.


MarkL

Offline apokliptico

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Reply #4 - 06 April 2009, 12:35:03
Thanks for answering, but I meant the angle in which the glider touches the atmosphere. In earth normally its between 1 and 2
degrees...

Does anyone know that formula?



Offline ar81

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Reply #5 - 01 June 2009, 16:27:47
Vertical velocity ^2 + Horizontal  velocity ^2 = Velocity
Sine(Angle of descent) = Vertical velocity/Velocity

« Last Edit: 01 June 2009, 16:27:47 by ar81 »